In this challenge, we wanted to find the area of the shaded region. First, we must note that the white triangle is a right triangle. the side that is 1.01dm is a diameter of the large black circle. With that information, we can find that the area of the big circle is 2550.25πmm2, and the area of the triangle is 990mm2. We also know that the semiperimeter of the triangle is 110mm. We can use the formula A=rs to find the radius of the small circle to be 9 mm. We then find it’s area to be 81πmm2. Putting this all together we get an anser of 2631.25πmm2 – 495mm2.